Print N lines of numbers such that every pair among numbers has a GCD K

CServer Side ProgrammingProgramming

GCD

GCD stands for Greatest Common Divisor of two or more integers excluding 0

Like, to find the greatest common divisor of 48 and 180

48 = 2 × 2 × 2 × 2 × 3

180 = 2 × 2 × 3 × 3 × 5

Greatest common divisor = 2 × 2 × 3 = 12.

In the given problem, N lines should be printed with elements have GCD as specified

Input : N=2 GCD=2
Ouput : 2-4-6-10
14-16-18-22

Algorithm

START
Step 1 -> take input n(e.g. 2) and k(e.g. 2) as int values and i
Step 2-> Loop For i to 0 and i<n and i++
   Print (k * (6 * i + 1))
   Print (k * (6 * i + 2))
   Print (k * (6 * i +3))
   Print (k * (6 * i + 5))
   Print \n
Step 3 -> end loop
STOP

Example

#include<stdio.h>
int main() {
   int i,n = 2, k = 2;
   for (i = 0; i < n; i++) {
      printf("%d-",(k * (6 * i + 1)));
      printf("%d-",(k * (6 * i + 2)));
      printf("%d-",(k * (6 * i + 3)));
      printf("%d",(k * (6 * i + 5)));
      printf("\n");
   }
   return 0;
}

Output

if we run above program then it will generate following output.

2-4-6-10
14-16-18-22
raja
Published on 30-Jul-2019 11:55:58
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