# Print first N terms of series (0.25, 0.5, 0.75, …) in fraction representation

CServer Side ProgrammingProgramming

Input N which is equivalent to the number till where series should be printed

Input : N=5
Output : 0 ¼ ½ ¾ 1

## Algorithm

START
Step 1 -> declare start variables as int num , den, i, n
Step 2 -> input number in n
Step 3 -> Loop For from i to 0 and i<n and i++
Outer If i%2=0
Inner IF i%4=0
Set num=i/4 and den=0
End Outer IF
Else
Set num=i/2 and den=2
End Else
End Outer IF
Else
Set num = I and den = 4
End Else
If den != 0
Print num and den
End IF
Else
Print num
End Else
Step 4 -> End For Loop
STOP

## Example

#include <stdio.h>
int main(int argc, char const *argv[]) {
int num, den;
int i, n;
printf("Enter series limit\n");
scanf("%d", &n); //Till where the series will be starting from zero
for (i = 0; i < n; i++) {
if (i%2==0) { //Checking the numerator is odd or even
if(i%4==0) { //If the numerator divisible by 4 divide it
num = i/4;
den = 0;
}
else  {//if not divisible by 4 its even number divisible by 2
num = i/2;
den = 2;
}
}
else { //Assigning numerator and denominator value if the number is odd
num = i;
den = 4;
}
if (den != 0) { //if denominator is not zero then print in fraaction form
printf("%d/%d\n",num, den);
}
else //else print in a normal number form
printf("%d\n", num);
}
return 0;
}

## Output

If we run the above program then it will generate the following output

Enter series limit
5
0
1/4
1/2
3/4
1