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Print first N terms of series (0.25, 0.5, 0.75, …) in fraction representation
Input N which is equivalent to the number till where series should be printed
Input : N=5 Output : 0 ¼ ½ ¾ 1
Algorithm
START Step 1 -> declare start variables as int num , den, i, n Step 2 -> input number in n Step 3 -> Loop For from i to 0 and i<n and i++ Outer If i%2=0 Inner IF i%4=0 Set num=i/4 and den=0 End Outer IF Else Set num=i/2 and den=2 End Else End Outer IF Else Set num = I and den = 4 End Else If den != 0 Print num and den End IF Else Print num End Else Step 4 -> End For Loop STOP
Example
#include <stdio.h>
int main(int argc, char const *argv[]) {
int num, den;
int i, n;
printf("Enter series limit
");
scanf("%d", &n); //Till where the series will be starting from zero
for (i = 0; i < n; i++) {
if (i%2==0) { //Checking the numerator is odd or even
if(i%4==0) { //If the numerator divisible by 4 divide it
num = i/4;
den = 0;
}
else {//if not divisible by 4 its even number divisible by 2
num = i/2;
den = 2;
}
}
else { //Assigning numerator and denominator value if the number is odd
num = i;
den = 4;
}
if (den != 0) { //if denominator is not zero then print in fraaction form
printf("%d/%d
",num, den);
}
else //else print in a normal number form
printf("%d
", num);
}
return 0;
}Output
If we run the above program then it will generate the following output
Enter series limit 5 0 1/4 1/2 3/4 1
Updated on: 30-Jul-2019
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