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Print 1 2 3 infinitely using threads in C
Here, we have to print 1 2 3 sequences repeatedly infinite number of times using threads in the c programming language.
Let’s see the sample output that we want from our code,
1 2 3 1 2 3 1 2 3 1 2 3
For this, we will have to use three threads that are running side by side in the C programming language. And a variable that is initialized to one in the first thread whose value will be updated based on its last value. And run an infinite loop in the function.
Example
Let’s see the program to implement our solution,
#include <stdio.h>
#include <pthread.h>
pthread_cond_t cond1 = PTHREAD_COND_INITIALIZER;
pthread_cond_t cond2 = PTHREAD_COND_INITIALIZER;
pthread_cond_t cond3 = PTHREAD_COND_INITIALIZER;
pthread_mutex_t lock = PTHREAD_MUTEX_INITIALIZER;
int value = 1;
void *foo(void *n){
while(1) {
pthread_mutex_lock(&lock);
if (value != (int)*(int*)n) {
if ((int)*(int*)n == 1) {
pthread_cond_wait(&cond1, &lock);
} else if ((int)*(int*)n == 2) {
pthread_cond_wait(&cond2, &lock);
} else {
pthread_cond_wait(&cond3, &lock);
}
}
printf("%d ", *(int*)n);
if (value == 3) {
value = 1;
pthread_cond_signal(&cond1);
}
else if(value == 1) {
value = 2;
pthread_cond_signal(&cond2);
} else if (value == 2) {
value = 3;
pthread_cond_signal(&cond3);
}
pthread_mutex_unlock(&lock);
}
return NULL;
}
int main(){
pthread_t tid1, tid2, tid3;
int n1 = 1, n2 = 2, n3 = 3;
pthread_create(&tid1, NULL, foo, (void *)&n1);
pthread_create(&tid2, NULL, foo, (void *)&n2);
pthread_create(&tid3, NULL, foo, (void *)&n3);
while(1);
return 0;
}Output
1 2 3 1 2 3 1 2 3 1 2 3 1 2 3….
Updated on: 03-Feb-2020
286 Views
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