Primitive root of a prime number n modulo n in C++

C++Server Side ProgrammingProgramming

In this problem, we are given a prime number N. our task is to print the primitive root of prime number N modulo N.

Primitive root of prime number N is an integer x lying between [1, n-1] such that all values of xk (mod n) where k lies in [0, n-2] are unique.

Let’s take an example to understand the problem,

Input: 13
Output: 2

To solve this problem, we have to use mathematical function called Euler’s Totient Function.

Euler’s Totient Function is the count of numbers from 1 to n which are relatively prime to the number n.

A number i is relatively prime if GCD (i, n) = 1.

In solution, if the multiplicative order of x modulo n is equal to Euler’s Totient Function, then the number is primitive root otherwise not. We will check for all relative primes.

Note: Euler’s Totient Function of a prime number n=n-1

The below code will show the implementation of our solution,

Example

 Live Demo

#include<bits/stdc++.h>
using namespace std;
bool isPrimeNumber(int n) {
   if (n <= 1) return false;
   if (n <= 3) return true;
   if (n%2 == 0 || n%3 == 0) return false;
   for (int i=5; i*i<=n; i=i+6)
      if (n%i == 0 || n%(i+2) == 0)
         return false;
   return true;
}
int power(int x, unsigned int y, int p) {
   int res = 1;
   x = x % p;
   while (y > 0){
      if (y & 1)
      res = (res*x) % p;
      y = y >> 1;
      x = (x*x) % p;
   }
   return res;
}
void GeneratePrimes(unordered_set<int> &s, int n) {
   while (n%2 == 0){
      s.insert(2);
      n = n/2;
   }
   for (int i = 3; i <= sqrt(n); i = i+2){
      while (n%i == 0){
         s.insert(i);
         n = n/i;
      }
   }
   if (n > 2)
   s.insert(n);
}
int findPrimitiveRoot(int n) {
   unordered_set<int> s;
   if (isPrimeNumber(n)==false)
   return -1;
   int ETF = n-1;
   GeneratePrimes(s, ETF);
   for (int r=2; r<=ETF; r++){
      bool flag = false;
      for (auto it = s.begin(); it != s.end(); it++){
         if (power(r, ETF/(*it), n) == 1){
            flag = true;
            break;
         }
      }
      if (flag == false)
      return r;
   }
   return -1;
}
int main() {
   int n= 13;
   cout<<" Smallest primitive root of "<<n<<" is "<<findPrimitiveRoot(n);
   return 0;
}

Output

Smallest primitive root of 13 is 2
raja
Published on 03-Feb-2020 14:57:26
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