Picking the odd one out in JavaScript

We are required to write a JavaScript function that takes in an array of literals that contains all similar elements but one.

Our function should return the unlike number.

Therefore, let’s write the code for this function −

Example

The code for this will be −

const arr = [2, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4];
// considering that the length of array is atleast 3
const findUnlike = arr => {
   for(let i = 1; i < arr.length-1; i++){
      if(arr[i] - arr[i-1] !== 0 && arr[i]-arr[i+1] === 0){
         return arr[i-1];
      }else if(arr[i] - arr[i-1] !== 0 && arr[i]-arr[i+1] === 0){
         return arr[i]
      }else if(arr[i] - arr[i-1] === 0 && arr[i]-arr[i+1] !== 0){
         return arr[i+1];
      };
      continue;
   };
};
console.log(findUnlike(arr));

Output

The output in the console will be −

2

AmitDiwan

Published on 19-Oct-2020 10:27:49

• Related Questions & Answers
• Picking out uniques from an array in JavaScript
• Picking the triangle edges with maximum perimeter JavaScript
• Picking the largest elements from multidimensional array in JavaScript
• Picking index randomly from array in JavaScript
• Picking all the numbers present in a string in JavaScript
• Explain cherry picking in Git
• Finding out the Harshad number JavaScript
• How to find the one integer that appears an odd number of times in a JavaScript array?
• Take an array and find the one element that appears an odd number of times in JavaScript
• Picking all elements whose value is equal to index in JavaScript
• Reverse only the odd length words - JavaScript
• Separate odd and even in JavaScript
• Fetching odd appearance number in JavaScript
• Odd even index difference - JavaScript
• N consecutive odd numbers JavaScript