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Performing distinct on multiple fields in MongoDB?
You can use $group operator along with aggregate framework to perform distinct on multiple fields. Let us first create a collection with documents −
> db.distinctOnMultipleFieldsDemo.insertOne(
... {
... "StudentFirstName" : "Chris",
... "StudentAge" : 21,
... "StudentCountryName": "US"
... }
... );
{
"acknowledged" : true,
"insertedId" : ObjectId("5cd2e518b64f4b851c3a13d7")
}
> db.distinctOnMultipleFieldsDemo.insertOne(
... {
... "StudentFirstName" : "Robert",
... "StudentAge" : 21,
... "StudentCountryName": "AUS"
... }
... );
{
"acknowledged" : true,
"insertedId" : ObjectId("5cd2e518b64f4b851c3a13d8")
}
> db.distinctOnMultipleFieldsDemo.insertOne(
... {
... "StudentFirstName" : "Chris",
... "StudentAge" : 22,
... "StudentCountryName": "UK"
... }
... );
{
"acknowledged" : true,
"insertedId" : ObjectId("5cd2e518b64f4b851c3a13d9")
}
> db.distinctOnMultipleFieldsDemo.insertOne(
... {
... "StudentFirstName" : "David",
... "StudentAge" : 24,
... "StudentCountryName": "AUS"
... }
... );
{
"acknowledged" : true,
"insertedId" : ObjectId("5cd2e518b64f4b851c3a13da")
}Following is the query to display all documents from a collection with the help of find() method −
> db.distinctOnMultipleFieldsDemo.find().pretty();
This will produce the following output −
{
"_id" : ObjectId("5cd2e518b64f4b851c3a13d7"),
"StudentFirstName" : "Chris",
"StudentAge" : 21,
"StudentCountryName" : "US"
}
{
"_id" : ObjectId("5cd2e518b64f4b851c3a13d8"),
"StudentFirstName" : "Robert",
"StudentAge" : 21,
"StudentCountryName" : "AUS"
}
{
"_id" : ObjectId("5cd2e518b64f4b851c3a13d9"),
"StudentFirstName" : "Chris",
"StudentAge" : 22,
"StudentCountryName" : "UK"
}
{
"_id" : ObjectId("5cd2e518b64f4b851c3a13da"),
"StudentFirstName" : "David",
"StudentAge" : 24,
"StudentCountryName" : "AUS"
}Following is the query to perform distinct on multiple fields in MongoDB −
> db.distinctOnMultipleFieldsDemo.aggregate([
... {
... $group:
... {
... _id:0,
... StudentFirstName: {$addToSet: '$StudentFirstName'},
... StudentAge: {$addToSet: '$StudentAge'},
... StudentCountryName: {$addToSet: '$StudentCountryName'},
... }}
... ]);This will produce the following output −
{ "_id" : 0, "StudentFirstName" : [ "David", "Robert", "Chris" ], "StudentAge" : [ 24, 22, 21 ], "StudentCountryName" : [ "UK", "AUS", "US" ] }
Updated on: 30-Jul-2019
2K+ Views
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