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Palindrome Integer in C++
Suppose we have a non-negative integer called num, we have to check whether it is a palindrome or not, but not using a string.
So, if the input is like 1331, then the output will be true.
To solve this, we will follow these steps −
ret := 0
x := num
while num > 0, do −
d := num mod 10
ret := ret * 10
ret := ret + d
num := num / 10
return true when x is same as ret
Let us see the following implementation to get better understanding −
Example
#include <bits/stdc++.h> using namespace std; class Solution { public: bool solve(int num) { int ret = 0; int x = num; while(num > 0){ int d = num % 10; ret *= 10; ret += d; num /= 10; } return x == ret; } }; main() { Solution ob; cout << (ob.solve(1331)); }
Input
1331
Output
1
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