What is the force of gravity on a body of mass $150\ kg$ lying on the surface of the earth? (Mass of earth $=6\times10^{24}\ kg$; Radius of earth $=6.4\times10^{6}\ m$; $G=6.7\times10^{-11}\ Nm^2kg^{-2}$)

 Here given, mass of the body $m=150\ kg$

Mass of the earth $M=6\times10^{24}\ kg$

Radius of earth $R=6.4\times10^{6}\ m$

Gravitational constant $G=6.7\times10^{-11}\ Nm^2kg^{-2}$

Therefore, the force of gravity on the body $F=G\frac{Mm}{R^2}$

Or $F=6.7\times10^{-11}\ Nm^2kg^{-2}\times\frac{6\times10^{24}\times150}{(6.4\times10^{6})^2}$

Or $F=1472.1\ N$

Therefore, the force of gravity on a body of mass $150\ kg$ lying on the surface of the earth is $1472.1\ N$.

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Updated on: 10-Oct-2022

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