What is the factorisation of $6st+4t+6-9s$?

To do:

We have to factorise $6st+4t+6-9s$.

Solution:

$6st-4t+6-9s=(6st-4t)+(6-9s)$

$=2t(3s-2)-3(3s-2)$                   [Taking $2t$ and $-3$ common respectively]

$=(2t-3)(3s-2)$ 

Therefore, $6st+4t+6-9s=(2t-3)(3s-2)$ .

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Updated on: 10-Oct-2022

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