Verify whether the indicated numbers are zeros of the polynomials corresponding to them in the following cases:$ f(x)=3 x+1, x=-\frac{1}{3} $

Given:

\( f(x)=3 x+1, x=-\frac{1}{3} \)

To do: 

We have to find whether the indicated numbers are zeros of the polynomials corresponding to them.

Solution:

To find whether $x=-\frac{1}{3}$ is a zero of $f(x)$ we have to check if $f(-\frac{1}{3})=0$.

Therefore,

$f(-\frac{1}{3})=3(-\frac{1}{3})+1$

$=-1+1$

$=0$

Therefore, $x=-\frac{1}{3}$ is the zero of $f(x)$.

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Updated on: 10-Oct-2022

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