The sum of a two digit number and the number obtained by interchanging the digits is always a multiple of optiona) 2 b) 11 c) 10 d) 12

Solution:

Let the ones place digit of the number be y and the digit in tens place be $x$.

So, the number becomes  $10x + y$.

When it is reversed, new number = $10y + x$.

Now,

Sum of these two numbers.

= $10x + y + 10y + x$

= $11x + 11y$

= $11 ( x + y )$

Therefore, the answer is 11.

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Updated on: 10-Oct-2022

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