Making use of the cube root table, find the cubes root of the following (correct to three decimal places)
7342
Given:
7342
To find:
We have to find the cube root of the given number correct to three decimal places using cube root table.
Solution:
$\sqrt[3]{7342}=\sqrt[3]{73.42 \times 100}$
$=\sqrt[3]{73.42} \times \sqrt[3]{100}$
$\sqrt[3]{73}=4.179$
$\sqrt[3]{74}=4.198$
For the difference $(74-73)=1$,
The difference in the values $=4.198-4.179$
$=0.019$
This implies,
For the difference of $0.42$,
The difference in the values $=0.019 \times 0.42$
$=0.00798$
$=0.008$
Therefore,
$\sqrt[3]{73.42}=4.179+0.008$
$=4.187$
$\sqrt[3]{100}=4.642$
$\sqrt[3]{7342} =\sqrt[3]{73.42} \times \sqrt[3]{100}$
$=4.642 \times 4.187$
$=19.436054$
$=19.436$
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