Find product of:

$(3m\ -\ 4n)$ and $(2m\ -\ 3n)$

Given: $(3m\ -\ 4n)$ and $(2m\ -\ 3n)$.

To find: Here we have to find the product of $(3m\ -\ 4n)$ and $(2m\ -\ 3n)$.

Solution:

$( 3m\ -\ 4n) \ \times \ ( 2m\ -\ 3n)$

$=\ 3m( 2m\ -\ 3n) \ -\ 4n( 2m\ -\ 3n)$

$=\ 6m^{2} \ -\ 9mn\ -\ 8mn\ +\ 12n^{2}$

$=\ \mathbf{6m^{2} \ -\ 17mn\ +\ 12n^{2}}$

So, the product of $(3m\ -\ 4n)$ and $(2m\ -\ 3n)$ is $6m^{2} \ -\ 17mn\ +\ 12n^{2}$.

Tutorialspoint

Updated on: 10-Oct-2022

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