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Check whether $3x + 2$ is the factor of the polynomial $15x^2 + x - 6$.
Given :
$f(x) = 15x^2 + x - 6, g(x) =3x+2$ are the given polynomials.
To find :
We have to check g(x) is the factor of f(x).
Solution :
If g(x) is a factor of f(x) then $f(\frac{-2}{3}) = 0$.
$f(\frac{-2}{3}) = 15 (\frac{-2}{3})^2+\frac{-2}{3}-6$
$= 15\times \frac{4}{9} -\frac{-2}{3}-6$
$= 5\times\frac{4}{9} -\frac{-2}{3}-6$
$= \frac{20}{3} - \frac{-2}{3}-6$
$= \frac{20-2-6\times3}{3}$
$=\frac{(18-18)}{3}$
= 0
$f(\frac{-2}{3})=0$
Therefore, $3x+2$ is a factor of $15x^2 + x - 6$.
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