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ORDER BY records in MySQL based on a condition
For this, you can use ORDER BY IF(). Let us first create a table −
mysql> create table DemoTable ( Name varchar(50), Score int ); Query OK, 0 rows affected (0.72 sec)
Insert some records in the table using insert command −
mysql> insert into DemoTable values('Chris',98); Query OK, 1 row affected (0.16 sec) mysql> insert into DemoTable values('David',45); Query OK, 1 row affected (0.13 sec) mysql> insert into DemoTable values('Bob',56); Query OK, 1 row affected (0.12 sec) mysql> insert into DemoTable values('Sam',89); Query OK, 1 row affected (0.14 sec) mysql> insert into DemoTable values('Carol',78); Query OK, 1 row affected (0.14 sec)
Display all records from the table using select statement −
mysql> select *from DemoTable;
This will produce the following output −
+-------+-------+ | Name | Score | +-------+-------+ | Chris | 98 | | David | 45 | | Bob | 56 | | Sam | 89 | | Carol | 78 | +-------+-------+ 5 rows in set (0.00 sec)
Following is the query to order records in MySQL based on a condition −
mysql> select *from DemoTable order by if(Name='Sam',1,0) ASC,Score DESC;
This will produce the following output −
+-------+-------+ | Name | Score | +-------+-------+ | Chris | 98 | | Carol | 78 | | Bob | 56 | | David | 45 | | Sam | 89 | +-------+-------+ 5 rows in set (0.00 sec)
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