Only return fields which appear a certain number of times using MySQL DISTINCT?

CsharpServer Side ProgrammingProgramming

To return fields appearing a certain number of times, the syntax is as follows −

select distinct yourColumnName, count(yourColumnName)
from yourTableName
where yourColumnName LIKE 'J%'
group by yourColumnName
having count(*) > 1
order by yourColumnName;

Let us first create a table −

mysql> create table DemoTable1500
   -> (
   -> Name varchar(20)
   -> );
Query OK, 0 rows affected (0.86 sec)

Insert some records in the table using insert command −

Mysql> insert into DemoTable1500 values(‘Adam’);
Query OK, 1 row affected (0.23 sec)
mysql> insert into DemoTable1500 values('John');
Query OK, 1 row affected (0.09 sec)
mysql> insert into DemoTable1500 values('Mike');
Query OK, 1 row affected (0.09 sec)
mysql> insert into DemoTable1500 values('John');
Query OK, 1 row affected (0.09 sec)
mysql> insert into DemoTable1500 values('Jace');
Query OK, 1 row affected (0.12 sec)
mysql> insert into DemoTable1500 values('Jace');
Query OK, 1 row affected (0.12 sec)
mysql> insert into DemoTable1500 values('Jackie');
Query OK, 1 row affected (0.06 sec)

Display all records from the table using select statement −

mysql> select * from DemoTable1500;

This will produce the following output −

+--------+
| Name   |
+--------+
| Adam   |
| John   |
| Mike   |
| John   |
| Jace   |
| Jace   |
| Jackie |
+--------+
7 rows in set (0.00 sec)

Following is the query to return fields which appear a certain number of times using MySQL DISTINCT −

mysql> select distinct Name, count(Name)
   -> from DemoTable1500
   -> where Name LIKE 'J%'
   -> group by Name
   -> having count(*) > 1
   -> order by Name;

This will produce the following output −

+------+-------------+
| Name | count(Name) |
+------+-------------+
| Jace |           2 |
| John |           2 |
+------+-------------+
2 rows in set (0.00 sec)
raja
Published on 11-Dec-2019 05:47:49
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