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Number of n digit stepping numbers in C++
The stepping number is a number where the difference between the consecutive digits is 1. You are given a number n representing the number of digits. You need to count the total number of stepping numbers with n digits.
Let's see an example.
Input
2
Output
17
The lowest number of 2 digits is 10 and highest number of 2 digits is 99. There are 17 stepping numbers in between them.
Algorithm
- Initialise the number n.
- Initialise the count to 0.
- Find the lowest number of n digits i.e.., pow(10, n - 1).
- Find the highest number of n digits i.e.., pow(10, n) - 1.
- Write a loop that iterates from the lowest n digit number to highest n digit number.
- Check whether the current number is stepping number or not.
- Check the difference between consecutive pair of digits in the number.
- If the result of the any difference is not 1, then return false else true.
- Increment the count if the current number is a stepping number.
- Return the count.
Implementation
Following is the implementation of the above algorithm in C++
#include <bits/stdc++.h>
using namespace std;
bool isSteppingNumber(int n) {
int previousDigit = -1;
while (n) {
int currentDigit = n % 10;
if (previousDigit != -1 && abs(previousDigit - currentDigit) != 1) {
return false;
}
previousDigit = currentDigit;
n /= 10;
}
return true;
}
int getSteppingNumbersCount(int n) {
int lowestNumber = pow(10, n - 1), highestNumber = pow(10, n) - 1;
int count = 0;
for (int i = lowestNumber; i <= highestNumber; i++) {
if (isSteppingNumber(i)) {
count += 1;
}
}
return count;
}
int main() {
int n = 3;
cout << getSteppingNumbersCount(n) << endl;
return 0;
}Output
If you run the above code, then you will get the following result.
32
Updated on: 26-Oct-2021
105 Views
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