Number is divisible by 29 or not in C++

It's a straightforward problem. We can use the modulo (%) operator to check whether the given number is divisible by 29 or not. Let's see some examples.

Input

29
254

Output

1
0

Algorithm

Implementation

Following is the implementation of the above algorithm in C++

#include 
using namespace std;
bool isDivisibleBy29(long long n) {
   return n % 29 == 0;
}
int main() {
      cout 
Output
If you run the above code, then you will get the following result.
1
1
0