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MySQL select any one field out of two with respect to the value of a third field?
For this, use IF(). Let us first create a table −
mysql> create table DemoTable -> ( -> PlayerName varchar(100), -> PlayerScore int, -> PlayerStatus varchar(100) -> ); Query OK, 0 rows affected (0.58 sec)
Insert some records in the table using insert command −
mysql> insert into DemoTable values('John',88,'BAD');
Query OK, 1 row affected (0.13 sec)
mysql> insert into DemoTable values('Chris',78,'BAD');
Query OK, 1 row affected (0.16 sec)
mysql> insert into DemoTable values('Robert',90,'BAD');
Query OK, 1 row affected (0.15 sec)
mysql> insert into DemoTable values('David',80,'BAD');
Query OK, 1 row affected (0.23 sec)Display all records from the table using select statement −
mysql> select *from DemoTable;
Output
+------------+-------------+--------------+ | PlayerName | PlayerScore | PlayerStatus | +------------+-------------+--------------+ | John | 88 | BAD | | Chris | 78 | BAD | | Robert | 90 | BAD | | David | 80 | BAD | +------------+-------------+--------------+ 4 rows in set (0.00 sec)
Following is the query to select any one field out of two with respect to the value of a third field −
mysql> select PlayerScore,if(PlayerScore > 80 , PlayerName ,PlayerStatus) AS Result from DemoTable;
Output
+-------------+--------+ | PlayerScore | Result | +-------------+--------+ | 88 | John | | 78 | BAD | | 90 | Robert | | 80 | BAD | +-------------+--------+ 4 rows in set (0.00 sec)
Updated on: 30-Jul-2019
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