MySQL select any one field out of two with respect to the value of a third field?
For this, use IF(). Let us first create a table −
mysql> create table DemoTable
-> (
-> PlayerName varchar(100),
-> PlayerScore int,
-> PlayerStatus varchar(100)
-> );
Query OK, 0 rows affected (0.58 sec)
Insert some records in the table using insert command −
mysql> insert into DemoTable values('John',88,'BAD');
Query OK, 1 row affected (0.13 sec)
mysql> insert into DemoTable values('Chris',78,'BAD');
Query OK, 1 row affected (0.16 sec)
mysql> insert into DemoTable values('Robert',90,'BAD');
Query OK, 1 row affected (0.15 sec)
mysql> insert into DemoTable values('David',80,'BAD');
Query OK, 1 row affected (0.23 sec)Display all records from the table using select statement −
mysql> select *from DemoTable;
Output
+------------+-------------+--------------+
| PlayerName | PlayerScore | PlayerStatus |
+------------+-------------+--------------+
| John | 88 | BAD |
| Chris | 78 | BAD |
| Robert | 90 | BAD |
| David | 80 | BAD |
+------------+-------------+--------------+
4 rows in set (0.00 sec)
Following is the query to select any one field out of two with respect to the value of a third field −
mysql> select PlayerScore,if(PlayerScore > 80 , PlayerName ,PlayerStatus) AS Result from DemoTable;
Output
+-------------+--------+
| PlayerScore | Result |
+-------------+--------+
| 88 | John |
| 78 | BAD |
| 90 | Robert |
| 80 | BAD |
+-------------+--------+
4 rows in set (0.00 sec)
Published on 10-Jul-2019 16:06:22
