MySQL query to select three highest values and sort alphabetically on the basis of corresponding column with name

MySQLMySQLi Database

For this, you can use the ORDER BY clause. Let us first create a table −

mysql> create table DemoTable
(
   Name varchar(40),
   Score int
);
Query OK, 0 rows affected (1.11 sec)

Insert some records in the table using insert command −

mysql> insert into DemoTable values('Chris',45);
Query OK, 1 row affected (0.26 sec)
mysql> insert into DemoTable values('Bob',98);
Query OK, 1 row affected (0.10 sec)
mysql> insert into DemoTable values('David',78);
Query OK, 1 row affected (0.17 sec)
mysql> insert into DemoTable values('Mike',96);
Query OK, 1 row affected (0.14 sec)
mysql> insert into DemoTable values('Carol',43);
Query OK, 1 row affected (0.20 sec)

Display all records from the table using select statement −

mysql> select *from DemoTable;

This will produce the following output −

+-------+-------+
| Name  | Score |
+-------+-------+
| Chris |    45 |
| Bob   |    98 |
| David |    78 |
| Mike  |    96 |
| Carol |    43 |
+-------+-------+
5 rows in set (0.00 sec)

Following is the query to select three highest values from “Score” column and sort the corresponding “Name” column alphabetically −

mysql> select *from (select Name,Score from DemoTable order by Score desc,Name asc limit 3) tbl
order by Name;

This will produce the following output −

+-------+-------+
| Name  | Score |
+-------+-------+
| Bob   |    98 |
| David |    78 |
| Mike  |    96 |
+-------+-------+
3 rows in set (0.03 sec)
raja
Published on 01-Oct-2019 08:01:49
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