MySQL query to display records on the basis of conditions IS NULL OR !=1;?

Let us first create a table −

mysql> create table DemoTable
(
   Id int NOT NULL AUTO_INCREMENT PRIMARY KEY,
   Name varchar(100),
   Score int
);
Query OK, 0 rows affected (1.10 sec)

Insert some records in the table using insert command −

mysql> insert into DemoTable(Name,Score) values('John',45);
Query OK, 1 row affected (0.14 sec)
mysql> insert into DemoTable(Name,Score) values('Chris',null);
Query OK, 1 row affected (0.14 sec)
mysql> insert into DemoTable(Name,Score) values('David',null);
Query OK, 1 row affected (0.11 sec)
mysql> insert into DemoTable(Name,Score) values('Bob',1);
Query OK, 1 row affected (0.11 sec)

Display all records from the table using select statement −

mysql> select *from DemoTable;

This will produce the following output −

+----+-------+-------+
| Id | Name  | Score |
+----+-------+-------+
|  1 | John  | 45    |
|  2 | Chris | NULL  |
|  3 | David | NULL  |
|  4 | Bob   | 1     |
+----+-------+-------+
4 rows in set (0.00 sec)

Following is the query to display records on the basis of conditions IS NULL OR !=1 −

mysql> select *from DemoTable where Score IS NULL OR Score!=1;

This will produce the following output −

+----+-------+-------+
| Id | Name  | Score |
+----+-------+-------+
|  1 | John  | 45    |
|  2 | Chris | NULL  |
|  3 | David | NULL  |
+----+-------+-------+
3 rows in set (0.00 sec)

AmitDiwan

Published on 30-Sep-2019 07:16:22

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