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MySQL query to display only the records that contains single word?
For this, you can filter records on the basis of LIKE. Let us first create a table −
mysql> create table DemoTable ( Name varchar(50) ); Query OK, 0 rows affected (0.50 sec)
Insert some records in the table using insert command −
mysql> insert into DemoTable values('John Smith');
Query OK, 1 row affected (0.12 sec)
mysql> insert into DemoTable values('John');
Query OK, 1 row affected (0.10 sec)
mysql> insert into DemoTable values('Adam Smith');
Query OK, 1 row affected (0.10 sec)
mysql> insert into DemoTable values('Carol');
Query OK, 1 row affected (0.10 sec)
mysql> insert into DemoTable values('David Miller');
Query OK, 1 row affected (0.10 sec)Display all records from the table using select statement −
mysql> select *from DemoTable;
This will produce the following output −
+--------------+ | Name | +--------------+ | John Smith | | John | | Adam Smith | | Carol | | David Miller | +--------------+ 5 rows in set (0.00 sec)
Following is the query to display records containing a single word. NOT LIKE is used here to exclude records with more than one word i.e. NOT LIKE '% %' −
mysql> select *from DemoTable where Name not like '% %';
This will produce the following output −
+-------+ | Name | +-------+ | John | | Carol | +-------+ 2 rows in set (0.00 sec)
Updated on: 04-Oct-2019
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