MySQL ORDER BY ASC and display NULLs at the bottom?
For this, use CASE statement with ORDER BY. Let us first create a table −
mysql> create table DemoTable1937
(
Name varchar(20)
);
Query OK, 0 rows affected (0.00 sec)
Insert some records in the table using insert command −
mysql> insert into DemoTable1937 values('Chris');
Query OK, 1 row affected (0.00 sec)
mysql> insert into DemoTable1937 values(NULL);
Query OK, 1 row affected (0.00 sec)
mysql> insert into DemoTable1937 values('Adam');
Query OK, 1 row affected (0.00 sec)
mysql> insert into DemoTable1937 values('John');
Query OK, 1 row affected (0.00 sec)
mysql> insert into DemoTable1937 values('');
Query OK, 1 row affected (0.00 sec)
mysql> insert into DemoTable1937 values(NULL);
Query OK, 1 row affected (0.00 sec)
mysql> insert into DemoTable1937 values('Bob');
Query OK, 1 row affected (0.00 sec)Display all records from the table using select statement −
mysql> select * from DemoTable1937;
This will produce the following output −
+-------+
| Name |
+-------+
| Chris |
| NULL |
| Adam |
| John |
| |
| NULL |
| Bob |
+-------+
7 rows in set (0.00 sec)
Here is the query to ORDER BY ASC and display NULLs at the bottom:
mysql> select * from DemoTable1937
order by case when Name IS NULL then 100
when Name='' then 101
else 103
end desc
,
Name asc;
This will produce the following output −
+-------+
| Name |
+-------+
| Adam |
| Bob |
| Chris |
| John |
| |
| NULL |
| NULL |
+-------+
7 rows in set (0.00 sec)
Published on 30-Dec-2019 07:53:00
