Move first element to end of a given Linked List in C++

Given a linked list, we have to move the first element to the end. Let's see an example.

Input

1 -> 2 -> 3 -> 4 -> 5 -> NULL

Output

2 -> 3 -> 4 -> 5 -> 1 -> NULL

Algorithm

Initialise the linked list.
Return if the linked list is empty or it has single node.
Find the last node of the linked list.
Make the second node as the new head.
Update the links of first and last nodes.

Implementation

Following is the implementation of the above algorithm in C++

#include <bits/stdc++.h>
using namespace std;
struct Node {
   int data;
   struct Node* next;
};
void moveFirstNodeToEnd(struct Node** head) {
   if (*head == NULL || (*head)->next == NULL) {
      return;
   }
   struct Node* firstNode = *head;
   struct Node* lastNode = *head;
   while (lastNode->next != NULL) {
      lastNode = lastNode->next;
   }
   *head = firstNode->next;
   firstNode->next = NULL;
   lastNode->next = firstNode;
}
void addNewNode(struct Node** head, int new_data) {
   struct Node* newNode = new Node;
   newNode->data = new_data;
   newNode->next = *head;
   *head = newNode;
}
void printLinkedList(struct Node* node) {
   while (node != NULL) {
      cout << node->data << "->";
      node = node->next;
   }
   cout << "NULL" << endl;
}
int main() {
   struct Node* head = NULL;
   addNewNode(&head, 1);
   addNewNode(&head, 2);
   addNewNode(&head, 3);
   addNewNode(&head, 4);
   addNewNode(&head, 5);
   addNewNode(&head, 6);
   addNewNode(&head, 7);
   addNewNode(&head, 8);
   addNewNode(&head, 9);
   moveFirstNodeToEnd(&head);
   printLinkedList(head);
   return 0;
}