MongoDB query to set a sub item in an array?

You can use positional $ operator. Let us first create a collection with documents −

> db.demo22.insertOne(
...    {
...       ProductId:101,
...
...       ProductDetails:
...       [
...          {
...             ProductFirstPrice: '35',
...             ProductSecondPrice: '75'
...          },
...          {
...             ProductFirstPrice: '',
...             ProductSecondPrice:''
...          },
...          {
...             ProductFirstPrice: '78',
...             ProductSecondPrice:'24'
...          }
...       ]
...    }
...
... );
{
   "acknowledged" : true,
   "insertedId" : ObjectId("5e14c0b422d07d3b95082e70")
}

Display all documents from a collection with the help of find() method −

> db.demo22.find().pretty();

This will produce the following output −

{
   "_id" : ObjectId("5e14c0b422d07d3b95082e70"),
   "ProductId" : 101,
   "ProductDetails" : [
      {
         "ProductFirstPrice" : "35",
         "ProductSecondPrice" : "75"
      },
      {
         "ProductFirstPrice" : "",
         "ProductSecondPrice" : ""
      },
      {
         "ProductFirstPrice" : "78",
         "ProductSecondPrice" : "24"
      }
   ]
}

Following is the MongoDB query to set a sub item in an array −

> db.demo22.update({ "ProductDetails.ProductFirstPrice" : "35" },
... { $set : { "ProductDetails.$.ProductFirstPrice" : "" }}, false, true);
WriteResult({ "nMatched" : 1, "nUpserted" : 0, "nModified" : 1 })

Display all documents from a collection with the help of find() method −

> db.demo22.find().pretty();

This will produce the following output −

{
   "_id" : ObjectId("5e14c0b422d07d3b95082e70"),
   "ProductId" : 101,
   "ProductDetails" : [
      {
         "ProductFirstPrice" : "",
         "ProductSecondPrice" : "75"
      },
      {
         "ProductFirstPrice" : "",
         "ProductSecondPrice" : ""
      },
      {
         "ProductFirstPrice" : "78",
         "ProductSecondPrice" : "24"
      }
   ]
}

AmitDiwan

Published on 01-Apr-2020 18:15:29