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MongoDB query to filter object where all elements from nested array match the condition
For this, use aggregate(). Let us first create a collection with documents −
> db.demo418.insertOne(
... {
... "details":[
... {
... "CountryName":"US",
... "Marks":45
... },
... {
... "CountryName":"US",
... "Marks":56
... },
...
... ],
... "Name":"John"
... }
... );
{
"acknowledged" : true,
"insertedId" : ObjectId("5e724324b912067e57771ae6")
}
> db.demo418.insertOne(
... {
... "details":[
... {
... "CountryName":"US",
... "Marks":78
... },
... {
... "CountryName":"UK",
... "Marks":97
... },
...
... ],
... "Name":"Mike"
... }
... );
{
"acknowledged" : true,
"insertedId" : ObjectId("5e724325b912067e57771ae7")
}
Display all documents from a collection with the help of find() method −
> db.demo418.find();
This will produce the following output −
{ "_id" : ObjectId("5e724324b912067e57771ae6"), "details" : [ { "CountryName" : "US", "Marks" : 45 }, { "CountryName" : "US", "Marks" : 56 } ], "Name" : "John" }
{ "_id" : ObjectId("5e724325b912067e57771ae7"), "details" : [ { "CountryName" : "US", "Marks" : 78 }, { "CountryName" : "UK", "Marks" : 97 } ], "Name" : "Mike" }
Following is the query to filter object where all elements from nested array match the condition −
> db.demo418.aggregate([
... {$unwind:"$details"},
... { $group: {
... _id: '$_id',
... details : { $first: '$details' },
... alldetails: { $sum: 1 },
... alldetailsmatch: { $sum: { $cond: [ { $eq: [ '$details.CountryName', "US" ] }, 1, 0 ] } },
... Name: { $first: '$Name' }
... }},
... { $project: {
... _id: 1,
... Name: 1,
... details: 1,
... arrayValue: { $cond: [ { $eq: [ '$alldetails', '$alldetailsmatch' ] }, 1, 0 ] }
... }},
... { $match: { 'arrayValue' : 1 } }
... ])
This will produce the following output −
{ "_id" : ObjectId("5e724324b912067e57771ae6"), "details" : { "CountryName" : "US", "Marks" : 45 }, "Name" : "John", "arrayValue" : 1 }Advertisements