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MongoDB query to exclude both the fields with FALSE
Use $or operator along with $expr operator for this. Let us first create a collection with documents, wherein one of fields is isMarried having true of false value −
> db.orTwoFieldsDemo.insertOne({"isLiveInUS":true,"isMarried":false});
{
"acknowledged" : true,
"insertedId" : ObjectId("5cdfd86abf3115999ed5120d")
}
> db.orTwoFieldsDemo.insertOne({"isLiveInUS":true,"isMarried":true});
{
"acknowledged" : true,
"insertedId" : ObjectId("5cdfd876bf3115999ed5120e")
}
> db.orTwoFieldsDemo.insertOne({"isLiveInUS":false,"isMarried":false});
{
"acknowledged" : true,
"insertedId" : ObjectId("5cdfd87dbf3115999ed5120f")
}Following is the query to display all documents from a collection with the help of find() method −
> db.orTwoFieldsDemo.find();
This will produce the following output −
{ "_id" : ObjectId("5cdfd86abf3115999ed5120d"), "isLiveInUS" : true, "isMarried" : false }
{ "_id" : ObjectId("5cdfd876bf3115999ed5120e"), "isLiveInUS" : true, "isMarried" : true }
{ "_id" : ObjectId("5cdfd87dbf3115999ed5120f"), "isLiveInUS" : false, "isMarried" : false }Following is the query to avoid both the FALSE values in two fields and display only fields with TRUE or one of the field with TRUE or another FALSE vice-versa −
> db.orTwoFieldsDemo.find({ $expr: { $or: [ "$isLiveInUS", "$isMarried" ] } });This will produce the following output −
{ "_id" : ObjectId("5cdfd86abf3115999ed5120d"), "isLiveInUS" : true, "isMarried" : false }
{ "_id" : ObjectId("5cdfd876bf3115999ed5120e"), "isLiveInUS" : true, "isMarried" : true }
Updated on: 30-Jul-2019
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