# Minimum number of nodes in an AVL Tree with given height using C++.

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## Problem statement

Given the height of an AVL tree, the task is to find the minimum number of nodes the tree can have.

If height = 0 then AVL tree can have one 1 node
If height = 5 then AVL tree can have minimum 20 nodes

## Algorithm

In an AVL tree, we have to maintain the height balance property, i.e. a difference in the height of the left and the right subtrees cannot be more than -1, 0 or 1 for each node. Using this property, we can create below recurrence relation −

1. If height = 0 then return 1
2. If height = 1 then return 2
3. If height > 1 then return (1 + getMinAVLNodes(h – 1) + getMinAVLNodes(h – 2))

## Example

#include <iostream>
using namespace std;
int getMinAVLNodes(int h){
if (h < 0) {
return 0;
}
if (h == 0 || h == 1) {
return h + 1;
}
return 1 + getMinAVLNodes(h - 1) + getMinAVLNodes(h -2);
}
int main(){
int h = 5;
cout << "Minimum nodes for " << h << " height = " << getMinAVLNodes(h) << endl;
return 0;
}

## Output

When you compile and execute the above program. It generates the following output −

Minimum nodes for 5 height = 20
Updated on 31-Oct-2019 07:15:22