# Minimum number of bottles required to fill K glasses in C++

C++Server Side ProgrammingProgramming

## Problem statement

Given N glasses having water, and a list of each of their capacity. The task is to find the minimum number of bottles required to fill out exactly K glasses. The capacity of each bottle is 100 units.

## Example

If N = 5, K = 4, capacity[] = {1, 2, 3, 2, 1}.

• Filling the glasses with capacities 2, 3, 2, requires 8units.
• This way, it's enough to open just 1 bottle.

## Algorithm

• To fill out exactly K glasses, take the K glasses with least capacity
• Total required bottles can be calculated as −

Ceil value of (Sum of capacities of 1st k glasses) / (Capacity of 1 bottle).

## Example

#include <iostream>
#include <algorithm>
#include <cmath>
using namespace std;
int minBottles(int *capacity, int n, int k) {
sort(capacity, capacity + n);
int sum = 0;
for (int i = 0; i < k; ++i) {
sum += capacity[i];
}
return ceil((double)sum/100);
}
int main() {
int capacity[] = {1, 2, 3, 2, 1};
cout << "Min bottles required = " <<minBottles(capacity, 5, 4) << endl;
return 0;
}

## Output

When you compile and execute above program. It generates following output −

Min bottles required = 1
Published on 22-Nov-2019 10:05:39