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Minimum insertions to make a Co-prime array in C++
In this section we will see another interesting problem. Suppose we have an array of N elements. We have to find minimum number of intersection points to make this array as co-prime array. In the co-prime array gcd of every two consecutive elements is 1. We have to print the array also.
Suppose we have elements like {5, 10, 20}. This is not co-prime array. Now by inserting 1 between 5, 10 and 10, 20, it will be co-prime array. So the array will be like {5, 1, 10, 1, 20}
Algorithm
makeCoPrime(arr, n): begin count := 0 for i in range 1 to n, do if gcd of arr[i] and arr[i – 1] is not 1, then increase count by 1 done display count value display the first element of arr for i in range 1 to n, do if gcd of arr[i] and arr[i – 1] is not 1, then display 1 display element arr[i] done end
Example
#include <iostream>
#include <algorithm>
using namespace std;
int makeCoPrime(int arr[], int n){
int count = 0;
for(int i = 1; i<n; i++){
if(__gcd(arr[i], arr[i - 1]) != i){
count++;
}
}
cout << "Number of intersection points: " << count << endl;
cout << arr[0] << " ";
for(int i = 1; i<n; i++){
if(__gcd(arr[i], arr[i - 1]) != i){
cout << 1 << " ";
}
cout << arr[i] << " ";
}
}
int main() {
int A[] = {2, 7, 28};
int n = sizeof(A)/sizeof(A[0]);
makeCoPrime(A, n);
}Output
Number of intersection points: 1 2 7 1 28
Updated on: 25-Sep-2019
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