Minimum flips required to maximize a number with k set bits in C++.

C++Server Side ProgrammingProgramming

Problem statement

Given two numbers n and k, we need to find the minimum number of flips required to maximize given number by flipping its bits such that the resulting number has exactly k set bits. Please note input must satify condition that k < number of bits in n.

Example

  • Let us suppose n = 9 and k = 2

  • Binary representation of 9 is − 1001. It contains 4 bits.

  • Largest 4 digit binary number with 2 set bits is − 1100 i.e. 12

  • To convert 1001 to 1100 we have to flip highlighed 2 bits

Algorithm

1. Count the number of bits in n. Let us call this variable as bitCount. we can use log2(n) function from math library as fllows:
   bitCount = log2(n) + 1;
2. Find largest number with k set bits as follows: maxNum = pow(2, k) - 1;
3. Find the largest number possible with k set bits and having exactly same number of bits as n as follows:
   maxNum = maxNum << (bitCount - k);
4. Calculate (n ^ maxNum) and count number of set bits.

Example

#include <iostream>
#include <cmath>
using namespace std;
int getSetBits(int n){
   int cnt = 0;
   while (n) {
      ++cnt;
      n = n & (n - 1);
   }
   return cnt;
}
int minFlipsRequired(int n, int k){
   int bitCount, maxNum, flipCount;
   bitCount = log2(n) + 1;
   maxNum = pow(2, k) - 1;
   maxNum = maxNum << (bitCount - k);
   flipCount = n ^ maxNum;
   return getSetBits(flipCount);
}
int main(){
   cout << "Minimum required flips: " << minFlipsRequired(9, 2) << "\n";
   return 0;
}

Output

When you compile and execute above program. It generates following output −

Minimum required flips: 2
raja
Published on 23-Sep-2019 10:47:51
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