# Merging two unsorted arrays in sorted order in C++.

## Problem statement

Write a function that takes two unsorted arrays and merges them into a new array in sorted order.

arr1[] = {10, 5, 7, 2}
arr2[] = {4, 17, 9, 3}
result[] = {2, 3, 4, 5, 7, 9, 10, 17}

## Algorithm

1. Merge two unsorted array into new array
2. Sort newly create array

## Example

#include <iostream>
#include <algorithm>
#define SIZE(arr) (sizeof(arr) / sizeof(arr[0]))
using namespace std;
void mergeAndSort(int *arr1, int n1, int *arr2, int n2, int *result){
merge(arr1, arr1 + n1, arr2, arr2 + n2, result);
sort(result, result + n1 + n2);
}
void displayArray(int *arr, int n){
for (int i = 0; i < n; ++i) {
cout << arr[i] << " ";
}
cout << endl;
}
int main(){
int arr1[] = {10, 5, 7, 2};
int arr2[] = {4, 17, 9, 3};
int result[SIZE(arr1) + SIZE(arr2)];
cout << "First array: " << endl;
displayArray(arr1, SIZE(arr1));
cout << "Second array: " << endl;
displayArray(arr1, SIZE(arr2));
mergeAndSort(arr1, SIZE(arr1), arr2, SIZE(arr2), result);
cout << "Merged and sorted array: " << endl;
displayArray(result, SIZE(arr1) + SIZE(arr2));
return 0;
}

## Output

When you compile and execute the above program. It generates the following output −

First array:
10 5 7 2
Second array:
10 5 7 2
Merged and sorted array:
2 3 4 5 7 9 10 17

Updated on: 31-Oct-2019

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