Merge k sorted arrays in Java

JavaServer Side ProgrammingProgramming

We are given an ‘n’ number of arrays, let's say we take three arrays i.e. arr1[], arr2[] and arr3[] of integer type. The task is to merge all the given integer arrays in such a manner that the resultant array is sorted in the runtime only.

Let us understand with example

Input 

Int

a[]={21,22,23,24};

int b[ ] ={28,31,35}

Output −int resultant[ ]={21,22,23,24,28,31,35}.

Explanation − The array elements are compared before they are added and added according to their suitable position in the resultant array.

Input 

int

a[]={1,3,5,7,9,11,13};

int b[ ] ={14,16,18}

int c[ ] ={19,20,21,22}

Output − int resultant[ ]={1,3,5,7,9,11,13,14,16,18,19,20,21,22}.

Explanation −The array elements are compared before they are added and added according to their suitable position in the resultant array.

Approach used in the below program is as follows −

  • Input three integer arrays let’s say, arr1[], arr2[] and arr3[] and a resultant array as result[] and set it to the call to a method as mergeSortedArray(new int[][] { arr1, arr2, arr3 })

  • Inside the method mergeSortedArray(new int[][] { arr1, arr2, arr3 })

    • Create a variable as a queue of type priority queue and a variable as total and set it to 0.

    • Start loop FOR from i to 0 till length of an array and add element from bucket of an array to the variable declared as queue and set total to total + arr[i].length.

    • Set m to 0 and declare result[] integer array.

    • Start while queue.isEmpty() = false then set ArrayBucket ac to queue.poll(), result[m++] to ac.arr[ac.index] and check IF ac.index less than ac.arr.length - 1 then set queue.add(new ArrayBucket(ac.arr, ac.index + 1))

    • Return result

Example

import java.util.Arrays;
import java.util.PriorityQueue;
class ArrayBucket implements Comparable<ArrayBucket>{
   int[] arr;
   int index;
   public ArrayBucket(int[] arr, int index){
      this.arr = arr;
      this.index = index;
   }
   @Override
   public int compareTo(ArrayBucket o){
      return this.arr[this.index] - o.arr[o.index];
   }
}
public class testClass{
   public static int[] mergeSortedArray(int[][] arr){
      PriorityQueue<ArrayBucket> queue = new
      PriorityQueue<ArrayBucket>();
      int total = 0;
      for (int i = 0; i < arr.length; i++){
         queue.add(new ArrayBucket(arr[i], 0));
         total = total + arr[i].length;
      }
      int m = 0;
      int result[] = new int[total];
      while (!queue.isEmpty()){
         ArrayBucket ac = queue.poll();
         result[m++] = ac.arr[ac.index];
         if (ac.index < ac.arr.length - 1){
            queue.add(new ArrayBucket(ac.arr, ac.index + 1));
         }
      }
      return result;
   }
   public static void main(String[] args){
      int[] arr1 = { 1, 3, 5, 7 };
      int[] arr2 = { 2, 4, 6, 8 };
      int[] arr3 = { 0, 9, 10, 11 };
      int[] result = mergeSortedArray(new int[][] { arr1, arr2, arr3 });
      System.out.println("The final merged sorted array is :- "+Arrays.toString(result));
   }
}

Output

If we run the above code it will generate the following Output

The final merged sorted array is :-[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11]
raja
Updated on 05-Nov-2021 05:07:13

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