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memcpy() function in C/C++
The function memcpy() is used to copy a memory block from one location to another. One is source and another is destination pointed by the pointer. This is declared in “string.h” header file in C language. It does not check overflow.
Here is the syntax of memcpy() in C language,
void *memcpy(void *dest_str, const void *src_str, size_t number)
Here,
dest_str − Pointer to the destination array.
src_str − Pointer to the source array.
number − The number of bytes to be copied from source to destination.
Here is an example of memcpy() in C language,
Example
#include <stdio.h> #include <string.h> int main () { char a[] = "Firststring"; const char b[] = "Secondstring"; memcpy(a, b, 5); printf("New arrays : %s\t%s", a, b); return 0; }
Output
New arrays : SeconstringSecondstring
In the above program, two char type arrays are initialized and memcpy() function is copying the source string ‘b’ to the destination string ‘a’.
char a[] = "Firststring"; const char b[] = "Secondstring"; memcpy(a, b, 5);
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