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Maximum length of the sub-array whose first and last elements are same in C++
In this problem, we are given an array of characters. Our task is to create a program to print the maximum length of the subarray whose first and last elements are same in C++.
Let’s take an example to understand the problem,
Input − array = {‘t’, ‘u’, ‘t’, ‘o’, ‘r’, ‘i’, ‘a’, ‘l’, ‘s’, ‘p’, ‘o’, ‘i’, ‘n’, ‘t’ }
Output − 14
Explanation −
The subarray {‘t’, ‘u’, ‘t’, ‘o’, ‘r’, ‘i’, ‘a’, ‘l’, ‘s’, ‘p’, ‘o’, ‘i’, ‘n’, ‘t’ } starts and ends with t.
To solve this problem, we find the first and last occurrence a character in the array and then using the formula −
subarray length = lastOccurrence - firstOccurrence + 1
We will find the maximum length of all outcomes.
Let’s solve an example to understand the solution,
Array = {a, b , a , c , b, a}
Element a , firstoccerrence at index 0, last occurrence at index 5
Subarray length = 5 - 0 + 1= 4
maxLength = 6
Element b , firstoccerrence at index 1, last occurrence at index 4
Subarray length = 4 - 1 + 1 = 4
maxLength = 6
Example
Program to print the maximum length of the subarray whose first and last elements are same −
#include <iostream>
using namespace std;
int maxSubArrLength(string arr, int n){
int firstOccurrence, lastOccurrence = -1;
int maxlength = 0;
char ch;
for (int i = 0; i < n; i++){
ch = arr[i];
firstOccurrence = lastOccurrence = i;
for(int j = i; j<n; j++){
if(arr[j] == ch)
lastOccurrence = j;
}
maxlength = max(maxlength, (lastOccurrence - firstOccurrence + 1));
}
return maxlength;
}
int main(){
string arr = "tutorialsPoint";
int n = arr.length();
cout<<"The maximum length of subarray whose first and last elements are same is "<<maxSubArrLength(arr, n);
return 0;
}Output
The maximum length of subarray whose first and last elements are same is 14
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