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Maximum element in a very large array using pthreads in C++
Problem statement
Given a very large array of integers, find maximum within the array using multithreading
Example
If input array is {10, 14, -10, 8, 25, 46, 85, 1673, 63, 65, 93, 101, 125, 50, 73, 548} then
maximum element in this array is 1673
Algorithm
- Let us call array size as total_elements
- Create N threads
- Each thread will process (total_elementes/N) array elements and will find maximum element from it.
- Finally compute the maximum from the maximum value reported by each thread.
Example
#include <stdio.h>
#include <pthread.h>
#include <stdlib.h>
#include <limits.h>
#define MAX 10
#define SIZE(arr) (sizeof(arr) / sizeof(arr[0])) typedef struct struct_max {
int start;
int end;
int thread_num;
} struct_max;
int arr[] = {10, 14, -10, 8, 25, 46, 85, 1673, 63, 65, 93, 101, 125, 50, 73, 548};
int max_values_from_threds[MAX];
void *thread_fun(void *arg) {
struct_max *s_max = (struct_max*)arg;
int start = s_max->start;
int end = s_max->end;
int thread_num = s_max->thread_num;
int cur_max_value = INT_MIN;
for (int i = start; i < end; ++i) {
if (arr[i] > cur_max_value) {
cur_max_value = arr[i];
}
}
max_values_from_threds[thread_num] = cur_max_value;
return NULL;
}
int main() {
int total_elements = SIZE(arr);
int n_threads = 4;
struct_max thread_arr[4];
for (int i = 0; i < 4; ++i) {
thread_arr[i].thread_num = i + 1;
thread_arr[i].start = i * 4;
thread_arr[i].end = thread_arr[i].start + 4;
}
pthread_t threads[4];
for (int i = 0; i < 4; ++i) {
pthread_create(&threads[i], NULL, thread_fun, &thread_arr[i]);
}
for (int i = 0; i < 4; ++i) {
pthread_join(threads[i], NULL);
}
int final_max_val = max_values_from_threds[0];
for (int i = 0; i < n_threads; ++i) {
if (max_values_from_threds[i] > final_max_val) {
final_max_val = max_values_from_threds[i];
}
}
printf("Maximum value = %d\n", final_max_val);
return 0;
}Output
When you compile and execute above program. It generates following output −
Maximum value = 1673
Updated on: 10-Jan-2020
329 Views
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