- Trending Categories
- Data Structure
- Networking
- RDBMS
- Operating System
- Java
- iOS
- HTML
- CSS
- Android
- Python
- C Programming
- C++
- C#
- MongoDB
- MySQL
- Javascript
- PHP

- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who

# Maximum difference between two elements such that larger element appears after the smaller number in C

We are given with an array of integers of size N. The array consists of integers in random order. The task is to find the maximum difference between two elements such that the larger element appears after the smaller number. That is Arr[j]-Arr[i] is maximum such that j>i.

**Input**

Arr[] = { 2,1,3,8,3,19,21}.

**Output** −The maximum difference between two elements such that the larger element appears after the smaller number − 20

**Explanation** − The maximum difference is between 21 and 1 and 21 appears after 1 in the array.

**Input**

Arr[] = {18, 2,8,1,2,3,2,6 }.

**Output** −The maximum difference between two elements such that the larger element appears after the smaller number − 6

**Explanation** − The maximum difference is between 8 and 2 and 8 appears after 2 in the array.

## Approach used in the below program is as follows

Declare an array of integers which contains pairs of sides of rectangle.( Arr[] )

Create a variable to store the size of the array. (n)

The function maxArea(int arr[],int n) is used to calculate the maximum area for rectangle. It takes an input array and its size as arguments.

Inside maxArea() we declared an array Dim[2] two store highest two sides found after traversing the sorted array (in descending order) arr[].

As arr[] is sorted in descending order the highest 4 sides must be in the beginning. We will iterate arr[] such that a pair of sides is found.

Initialize Dim[] with 0 at first.

Inside the while loop we put the condition that it continues till j<2 that there are no values found for dim[0] and dim[1] or the end of arr[] is reached. (i<n).

If a pair of such sides is found, ( if(arr[i]==arr[i+1]) ), then store it in dim[j] and increment j for next side.

Return the result as a product of dim[0] and dim[1].

Note − sort(arr,n) is supposed to sort arr in descending order.

## Example

#include <stdio.h> int maxDiff(int arr[], int n){ // Maximum difference found so far int MD = arr[1] - arr[0]; // Minimum number visited so far int min = arr[0]; for(int i = 1; i < n; i++){ if (arr[i] - min > MD) MD = arr[i] - min; if (arr[i] < min) min = arr[i]; } return MD; } /* Driver program to test above function */ int main(){ int arr[] = {2,5,7,3,4,12}; int n=6; // Function calling printf("Maximum difference is : %d ",maxDiff(arr, n)); return 0; }

## Output

If we run the above code it will generate the following output −

The maximum difference between two elements such that the larger element appears after the smaller number : 10

- Related Questions & Answers
- Number of smaller and larger elements - JavaScript
- Maximum sum such that no two elements are adjacent in C++
- Find maximum difference between nearest left and right smaller elements in C++
- Maximum sum such that no two elements are adjacent - Set 2 in C++
- Frequency of smaller and larger elements - JavaScript
- Maximum sum in circular array such that no two elements are adjacent in C++
- Maximum difference between two subsets of m elements in C
- Count Derangements (Permutation such that no element appears in its original position) in C++
- Maximum sum such that no two elements are adjacent Alternate Method in C++ program
- Find maximum difference between nearest left and right smaller elements in Python
- Find maximum number of elements such that their absolute difference is less than or equal to 1 in C++
- Find the element that appears once in an array where every other element appears twice in C++
- Rearrange array such that even index elements are smaller and odd index elements are greater in C++
- First element that appears even number of times in an array in C++
- Find the only element that appears b times using C++