Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
Physics
Chemistry
Biology
Mathematics
English
Economics
Psychology
Social Studies
Fashion Studies
Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
Maximize Time by Replacing β_β in a given 24-Hour Format Time
Maximizing time by replacing β_β in a given 24-hour format time is a problem that involves calculating the maximum possible time by replacing the missing digits in a given time in a 24-hour format. The task is to find the maximum time possible by replacing the characters ββ with any digit. In this tutorial, we will discuss how to solve this problem using the C++ programming language. We will provide a step-by-step explanation of the algorithm used to calculate the maximum possible time, along with the C++ code to implement the algorithm.
Additionally, we will include test examples to illustrate the problem and its solution, as well as an explanation of the test examples. By the end of this tutorial, readers will have a better understanding of how to solve this problem using C++ and will be able to apply this knowledge to solve similar problems in the future. So letβs get started!
Problem Statement
The objective is to determine the maximum possible time by substituting any digit in the positions marked with β_β in string S, which represents time in a 24-hour format.
Sample Example 1
Input
S = "23:4_"
Output
"23:49"
Explanation β In the given input string, the third character is replaced with '9' to obtain the maximum possible time. Therefore, the output is "23:49".
Sample Example 2
Input
S = "1_:22"
Output
"19:22"
Explanation β In the given input string, the first character is replaced with '1' to obtain the maximum possible hour in the 24-hour format. Therefore, the output is "19:22".
Note β In both examples, the input string S represents a time in a 24-hour format with a missing digit represented by a '_'. The objective is to replace the missing digit with any digit to obtain the maximum possible time. The first example demonstrates how the second digit in the minute's place can be replaced to obtain the maximum time. The second example shows how the first digit in the hour's place can be replaced to obtain the maximum hour in the 24-hour format.
Algorithm
Step 1 β Take input string S from the user.
Step 2 β Initialize the maximum hour and minute values to 23 and 59, respectively.
Step 3 β If the second digit in the minute's place is missing, replace it with '9'.
Step 4 β If the first digit in the hour's place is missing:
If the second digit is less than '4', replace it with '9'.
Otherwise, replace it with '3'.
Step 5 β If the second digit in the hour's place is missing:
If the first digit is less than '2' or also missing, replace it with '2'.
Otherwise, replace it with '1'.
Step 6 β Output the maximum possible time.
Example
Following are the programs to implement the above algorithm β
In the below programs, the missing digits in a given time are replaced to find the maximum possible time. The program checks and replaces the missing second digit in the minute's place with '9'. Then, it handles the missing first digit in the hour's place by replacing it with '2' if the second digit is less than '4', otherwise with '1'. Finally, if the second digit in the hour's place is missing, it replaces it with '3' if the first digit is less than '2', otherwise with '2'. The program outputs the maximum possible time based on the replacements made.
#include <stdio.h>
#include <string.h>
int main() {
char S[] = "1_:22";
printf("Given time with missing digits: %s\n", S);
// Initialize the maximum hour and minute values
int maxHour = 23;
int maxMinute = 59;
// If the second digit in the minute's place is missing, replace it with '9'
if (S[4] == '_') {
S[4] = '9';
}
// If the first digit in the hour's place is missing, replace it with '2' if the second digit is less than '4',
// otherwise replace it with '1'
if (S[1] == '_') {
if (S[0] < '2') {
S[1] = '9';
} else {
S[1] = '3';
}
}
// If the second digit in the hour's place is missing, replace it with '3' if the first digit is less than '2',
// otherwise replace it with '2'
if (S[0] == '_') {
if (S[1] < '4' || S[1] == '_') {
S[0] = '2';
} else {
S[0] = '1';
}
}
// Output the maximum possible time
printf("The maximum possible time is: %s\n", S);
return 0;
}
Output
Given time with missing digits: 1_:22 The maximum possible time is: 19:22
#include <iostream>
#include <algorithm>
int main() {
std::string S = "1_:22";
std::cout << "Given time with missing digits: " << S << std::endl;
// Initialize the maximum hour and minute values
int maxHour = 23;
int maxMinute = 59;
// If the second digit in the minute's place is missing, replace it with '9'
if (S[4] == '_') {
S[4] = '9';
}
// If the first digit in the hour's place is missing, replace it with '2' if the second digit is less than '4',
// otherwise replace it with '1'
if (S[1] == '_') {
if (S[0] < '2') {
S[1] = '9';
} else {
S[1] = '3';
}
}
// If the second digit in the hour's place is missing, replace it with '3' if the first digit is less than '2',
// otherwise replace it with '2'
if (S[0] == '_') {
if (S[1] < '4' || S[1] == '_') {
S[0] = '2';
} else {
S[0] = '1';
}
}
// Output the maximum possible time
std::cout << "The maximum possible time is: " << S << std::endl;
return 0;
}
Output
Given time with missing digits: 1_:22 The maximum possible time is: 19:22
public class MaximumTime {
public static String calculateMaximumTime(String S) {
// Initialize the maximum hour and minute values
int maxHour = 23;
int maxMinute = 59;
char[] chars = S.toCharArray();
// If the second digit in the minute's place is missing, replace it with '9'
if (chars[4] == '_') {
chars[4] = '9';
}
// If the first digit in the hour's place is missing, replace it with '2' if the second digit is less than '4',
// otherwise replace it with '1'
if (chars[1] == '_') {
if (chars[0] < '2') {
chars[1] = '9';
} else {
chars[1] = '3';
}
}
// If the second digit in the hour's place is missing, replace it with '3' if the first digit is less than '2',
// otherwise replace it with '2'
if (chars[0] == '_') {
if (chars[1] < '4' || chars[1] == '_') {
chars[0] = '2';
} else {
chars[0] = '1';
}
}
// Convert the character array back to a string
return new String(chars);
}
public static void main(String[] args) {
String inputStr = "1_:22";
System.out.println("Given time with missing digits: " + inputStr);
String result = calculateMaximumTime(inputStr);
System.out.println("The maximum possible time is: " + result);
}
}
Output
Given time with missing digits: 1_:22 The maximum possible time is: 19:22
def calculate_maximum_time(S):
# Initialize the maximum hour and minute values
max_hour = 23
max_minute = 59
# If the second digit in the minute's place is missing, replace it with '9'
S = list(S)
if S[4] == '_':
S[4] = '9'
# If the first digit in the hour's place is missing, replace it with '2' if the second digit is less than '4',
# otherwise replace it with '1'
if S[1] == '_':
if S[0] < '2':
S[1] = '9'
else:
S[1] = '3'
# If the second digit in the hour's place is missing, replace it with '3' if the first digit is less than '2',
# otherwise replace it with '2'
if S[0] == '_':
if S[1] < '4' or S[1] == '_':
S[0] = '2'
else:
S[0] = '1'
# Convert the list back to a string
result = ''.join(S)
return result
input_str = "1_:22"
print("Given time with missing digits:", input_str)
result = calculate_maximum_time(input_str)
print("The maximum possible time is:", result)
Output
Given time with missing digits: 1_:22 The maximum possible time is: 19:22
Conclusion
To sum up, the problem of maximizing time by replacing '_' in a given 24-hour format time can be easily solved using the algorithm and C++ code provided in this tutorial. By following the step-by-step approach and understanding the logic behind the algorithm, readers can gain valuable insights into solving similar problems. With the help of the test examples, readers can verify the correctness of their code and gain confidence in their programming skills.
76 Views
