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# Largest Even and Odd N-digit numbers in C++

In this tutorial, we are going to write a program that finds the largest even and odd number of n digits number.

Let's see the steps to solve the problem.

- Initialise the number n.
- The largest odd number is pow(10, n) - 1.
- The largest even number is odd - 1.

## Example

Let's see the code.

#include <bits/stdc++.h> using namespace std; void findEvenAndOddNumbers(int n) { int odd = pow(10, n) - 1; int even = odd - 1; cout << "Even: " << even << endl; cout << "Odd: " << odd << endl; } int main() { int n = 6; findEvenAndOddNumbers(n); return 0; }

## Output

If you run the above code, then you will get the following result.

Even: 999998 Odd: 999999

## Conclusion

If you have any queries in the tutorial, mention them in the comment section.

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