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Largest Even and Odd N-digit numbers in C++
In this tutorial, we are going to write a program that finds the largest even and odd number of n digits number.
Let's see the steps to solve the problem.
- Initialise the number n.
- The largest odd number is pow(10, n) - 1.
- The largest even number is odd - 1.
Example
Let's see the code.
#include <bits/stdc++.h>
using namespace std;
void findEvenAndOddNumbers(int n) {
int odd = pow(10, n) - 1;
int even = odd - 1;
cout << "Even: " << even << endl;
cout << "Odd: " << odd << endl;
}
int main() {
int n = 6;
findEvenAndOddNumbers(n);
return 0;
}Output
If you run the above code, then you will get the following result.
Even: 999998 Odd: 999999
Conclusion
If you have any queries in the tutorial, mention them in the comment section.
Updated on: 09-Apr-2021
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