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Kotlin Array - union() Function
The Kotlin array union() function is used to accumulate distinct elements of an array and other collections (list, set, etc.) into one set. This function returns the accumulated set containing distinct elements.
The set preserves the original array's element order and iterates unique elements from the other collection at the end, according to the order of other collections
Syntax
Following is the syntax of Kotlin array union() function −
infix fun <T> Array<out T>.union(other: Iterable<T>): Set<T>
Parameters
This function accept other collection as a parameters.
Return value
This function returns a set containing all distinct element from both collection.
Example 1
Following is a basic example to demonstrate the use of union() function to return a set containing elements of both collections −
fun main(args: Array<String>) { // Define an array val array = arrayOf(1, 2, 3, 4, 5, 6) // define a list val list = listOf(7, 8, 9) // Create a set using union function val to_set = array.union(list); println("Original array: ${array.joinToString(", ")}") println("Original list: $list") println("Set: $to_set") }
Output
The above code generate following output −
Original array: 1, 2, 3, 4, 5, 6 Original list: [7, 8, 9] Set: [1, 2, 3, 4, 5, 6, 7, 8, 9]
Example 2
Let's see another example. Here, we use the union function to return a set containing distinct elements of both collections −
fun main(args: Array<String>) { // Define an array val array = arrayOf<String>("Daisy", "Rose", "Lily", "Lotus") // define a list val list = listOf<String>("Daisy", "Sunflower", "Marigold") // Create a set using union function val to_set = array.union(list); println("Original array: ${array.joinToString(", ")}") println("Original list: $list") println("Set: $to_set") }
Output
Following is the output −
Original array: Daisy, Rose, Lily, Lotus Original list: [Daisy, Sunflower, Marigold] Set: [Daisy, Rose, Lily, Lotus, Sunflower, Marigold]
Example 3
Let's continue with the another example to crate a set from two arrays and demonstrate how duplicates are removed −
fun main(args: Array<String>) { // Define an array with some duplicate elements val array1 = arrayOf(1, 2, 3, 4, 2, 3, 5, 6, 7, 8, 6) // Define another array with some duplicate elements val array2 = arrayOf(1, 2, 10, 11, 9, 10) // Convert arrays to lists and perform union val intSet: Set<Int> = array1.toList().union(array2.toList()) // Display the original arrays and the resulting set println("Original array1: ${array1.joinToString(", ")}") println("Original array2: ${array2.joinToString(", ")}") println("Set: ${intSet.joinToString(", ")}") }
Output
The above code produce following output −
Original array1: 1, 2, 3, 4, 2, 3, 5, 6, 7, 8, 6 Original array2: 1, 2, 10, 11, 9, 10 Set: 1, 2, 3, 4, 5, 6, 7, 8, 10, 11, 9