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K-th Element of Two Sorted Arrays in C++
In this tutorial, we are going to write a program that finds the k-th element from thee merged array of two sorted arrays.
Let's see the steps to solve the problem.
- Initialise the two sorted arrays.
- Initialise an empty array of size m + n.
- Merge the two arrays into the new array.
- Return the k - 1 element from the merged array.
Example
Let's see the code.
#include <iostream>
using namespace std;
int findKthElement(int arr_one[], int arr_two[], int m, int n, int k) {
int sorted_arr[m + n];
int i = 0, j = 0, index = 0;
while (i < m && j < n) {
if (arr_one[i] < arr_two[j]) {
sorted_arr[index++] = arr_one[i++];
}else {
sorted_arr[index++] = arr_two[j++];
}
}
while (i < m) {
sorted_arr[index++] = arr_one[i++];
}
while (j < n) {
sorted_arr[index++] = arr_two[j++];
}
return sorted_arr[k - 1];
}
int main() {
int arr_one[5] = {1, 3, 5, 7, 9}, arr_two[5] = {2, 4, 6, 8, 10};
int k = 7;
cout << findKthElement(arr_one, arr_two, 5, 4, k) << endl;
return 0;
}Output
If you run the above code, then you will get the following result.
7
Conclusion
If you have any queries in the tutorial, mention them in the comment section.
Updated on: 09-Apr-2021
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