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JavaScript Find the first non-consecutive number in Array
We have to write a function that takes in an array and returns the index of the first nonconsecutive number from it. Like all the numbers will be in an arithmetic progression of common difference 1. But the number, which violates this rule, we have to return its index.
If all the numbers are in perfect order, we should return -1.
Let’s write the code for this function −
Example
const arr = [1,2,3,4,5,6,8,9,10];
const secondArr = [3,4,5,6,7,8,9,10,11,12,13,14,15];
const findException = (arr) => {
for(let i = 0; i < arr.length-1; i++){
if(arr[i+1] - arr[i] !== 1){
return i+1;
};
};
return -1;
};
console.log(findException(arr));
console.log(findException(secondArr));Output
The output in the console will be −
6 -1
Updated on 24-Aug-2020 06:02:50
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