java.util.regex.Pattern.compile() Method

Description

The java.util.regex.Pattern.compile(String regex) method compiles the given regular expression into a pattern.

Declaration

Following is the declaration for java.util.regex.Pattern.compile(String regex) method.

public static Pattern compile(String regex)

Parameters

• regex − The expression to be compiled.

Exceptions

• PatternSyntaxException − If the expression's syntax is invalid.

Example

The following example shows the usage of java.util.regex.Pattern.compile(String regex) method.

package com.tutorialspoint;

import java.util.regex.MatchResult;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class PatternDemo {
   private static final String REGEX = "(.*)(\\d+)(.*)";
   private static final String INPUT = "This is a sample Text, 1234, with numbers in between.";

   public static void main(String[] args) {
      // create a pattern
      Pattern pattern = Pattern.compile(REGEX);
      
      // get a matcher object
      Matcher matcher = pattern.matcher(INPUT); 

      if(matcher.find()) {
         //get the MatchResult Object 
         MatchResult result = matcher.toMatchResult();

         //Prints the offset after the last character matched.
         System.out.println("First Capturing Group - Match String end(): "+result.end());         
      }
   }
}

Let us compile and run the above program, this will produce the following result −

First Capturing Group - Match String end(): 53