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Java - RandomAccessFile writeLong(long v) method
Description
The Java RandomAccessFile writeLong(long v) method writes a long to the file as eight bytes, high byte first. The write starts at the current position of the file pointer.
writeLong(long v) method −
Writes a 64-bit (8-byte) long value to the file.
The bytes are written in big-endian order (most significant byte first).
The file pointer moves forward by 8 bytes.
You can read it back using readLong().
Declaration
Following is the declaration for java.io.RandomAccessFile.writeLong(long v) method.
public final void writeLong(long v)
Parameters
v − a long value to be written.
Return Value
This method does not return a value.
Exception
IOException − If an I/O error occurs.
Example - Usage of RandomAccessFile writeLong(long v) method
The following example shows the usage of RandomAccessFile writeLong(long v) method.
RandomAccessFileDemo.java
package com.tutorialspoint; import java.io.RandomAccessFile; import java.io.IOException; public class RandomAccessFileDemo { public static void main(String[] args) { try { long f = 184750874576l; // create a new RandomAccessFile with filename test RandomAccessFile raf = new RandomAccessFile("test.txt", "rw"); // write a long in the file raf.writeLong(f); // set the file pointer at 0 position raf.seek(0); // read long System.out.println(raf.readLong()); // set the file pointer at 0 position raf.seek(0); // write a long at the start raf.writeLong(20000000000l); // set the file pointer at 0 position raf.seek(0); // read long System.out.println(raf.readLong()); } catch (IOException ex) { ex.printStackTrace(); } } }
Output
Assuming we have a text file test.txt in current directory which has the following content. This file will be used as an input for our example program −
ABCDE
Let us compile and run the above program, this will produce the following result −
184750874576 20000000000
Example - Writing and Reading a Single Long Value
The following example shows the usage of RandomAccessFile writeLong(long v) method.
RandomAccessFileDemo.java
package com.tutorialspoint; import java.io.RandomAccessFile; import java.io.IOException; public class RandomAccessFileDemo { public static void main(String[] args) { try (RandomAccessFile raf = new RandomAccessFile("long1.dat", "rw")) { // Write a long value raf.writeLong(9876543210L); // Move the file pointer to the beginning raf.seek(0); // Read the long value back long value = raf.readLong(); System.out.println("Read long: " + value); } catch (IOException e) { e.printStackTrace(); } } }
Output
Let us compile and run the above program, this will produce the following result−
Read long: 9876543210
Explanation
9876543210L is stored as 8 bytes.
File content: 8 bytes in big-endian representing 9876543210.
readLong() reads exactly what was written.
Example - Writing Multiple Long Values and Reading Them
The following example shows the usage of RandomAccessFile writeLong(long v) method.
RandomAccessFileDemo.java
package com.tutorialspoint; import java.io.RandomAccessFile; import java.io.IOException; public class RandomAccessFileDemo { public static void main(String[] args) { try (RandomAccessFile raf = new RandomAccessFile("long2.dat", "rw")) { // Write multiple long values raf.writeLong(10000000000L); raf.writeLong(20000000000L); raf.writeLong(30000000000L); // Move pointer to the beginning raf.seek(0); // Read back the long values long a = raf.readLong(); long b = raf.readLong(); long c = raf.readLong(); System.out.println("Read values: " + a + ", " + b + ", " + c); } catch (IOException e) { e.printStackTrace(); } } }
Output
Let us compile and run the above program, this will produce the following result−
Read values: 10000000000, 20000000000, 30000000000
Explanation
Writes three long values (8 bytes each) → total 24 bytes.
seek(0) resets the file pointer to start.
readLong() reads them in the same order.