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Java.io.RandomAccessFile.readInt() Method
Description
The java.io.RandomAccessFile.readInt() method reads a signed 32-bit integer from this file. This method reads 4 bytes from the file, starting at the current file pointer.
Declaration
Following is the declaration for java.io.RandomAccessFile.readInt() method.
public final int readInt()
Parameters
NA
Return Value
This method returns the next four bytes of this file, interpreted as an int.
Exception
IOException − If an I/O error occurs.
EOFException − If this file reaches the end before reading four bytes.
Example
The following example shows the usage of java.io.RandomAccessFile.readInt() method.
package com.tutorialspoint; import java.io.*; public class RandomAccessFileDemo { public static void main(String[] args) { try { int i = 284; // create a new RandomAccessFile with filename test RandomAccessFile raf = new RandomAccessFile("c:/test.txt", "rw"); // write something in the file raf.writeInt(123); // set the file pointer at 0 position raf.seek(0); // print the int System.out.println("" + raf.readInt()); // set the file pointer at 0 position raf.seek(0); // write something in the file raf.writeInt(i); // set the file pointer at 0 position raf.seek(0); // print the int System.out.println("" + raf.readInt()); } catch (IOException ex) { ex.printStackTrace(); } } }
Assuming we have a text file c:/test.txt, which has the following content. This file will be used as an input for our example program −
ABCDE
Let us compile and run the above program, this will produce the following result −
123 284
java_io_randomaccessfile.htm
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