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Java.io.RandomAccessFile.readDouble() Method
Description
The java.io.RandomAccessFile.readDouble() method reads a double from this file. This method reads a long value, starting at the current file pointer, as if by the readLong method and then converts that long to a double using the longBitsToDouble method in class Double.
Declaration
Following is the declaration for java.io.RandomAccessFile.readDouble() method.
public final double readDouble()
Parameters
NA
Return Value
This method returns the next eight bytes of this file, interpreted as a double.
Exception
IOException − If an I/O error occurs.Not thrown if end-of-file has been reached.
EOFException − If this file reaches the end before reading eight bytes.
Example
The following example shows the usage of java.io.RandomAccessFile.readDouble() method.
package com.tutorialspoint; import java.io.*; public class RandomAccessFileDemo { public static void main(String[] args) { try { double d = 1.5987475; // create a new RandomAccessFile with filename test RandomAccessFile raf = new RandomAccessFile("c:/test.txt", "rw"); // write something in the file raf.writeDouble(765.497634); // set the file pointer at 0 position raf.seek(0); // read double System.out.println("" + raf.readDouble()); // set the file pointer at 0 position raf.seek(0); // write a double at the start raf.writeDouble(d); // set the file pointer at 0 position raf.seek(0); // read double System.out.println("" + raf.readDouble()); } catch (IOException ex) { ex.printStackTrace(); } } }
Assuming we have a text file c:/test.txt, which has the following content. This file will be used as an input for our example program −
ABCDE
Let us compile and run the above program, this will produce the following result −
765.497634 1.5987475