Java Regular expression to check if a string contains alphabet

Following is the regular expression to match alphabet in the given input −

"^[a-zA-Z]*$"

Where,

• ^ matches the starting of the sentence.
• [a-zA-z] matches the lower case and upper case letters.
• * indicates the occurrence for zero or more times.
• & indicates the end of the line.

Example 1

import java.util.Scanner;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class ContainsAlphabetExample {
   public static void main(String[] args) {
      Scanner sc = new Scanner(System.in);
      String names[] = new String[5];
      for(int i=0; i

Output
Enter your name:
krishna
Enter your name:
kasyap
Enter your name:
maruthi#
Enter your name:
Sai_Ram
Enter your name:
Vani.Viswanath
krishna is a valid name
kasyap is a valid name
maruthi# is not a valid name
Sai_Ram is not a valid name
Vani.Viswanath is not a valid name
Example 2
import java.util.Scanner;
public class Just {
   public static void main(String[] args) {
      Scanner sc = new Scanner(System.in);
      System.out.println("Enter your name: ");
      String name = sc.nextLine();
      String regex = "^[a-zA-Z]*$";
      boolean result = name.matches(regex);
      if(result) {
         System.out.println("Given name is valid");
      } else {
         System.out.println("Given name is not valid");
      }
   }
}
Output
Enter your name:
vasu#dev
Given name is not valid