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Java Program to sort an array in case-sensitive order
An array can be sorted in case-sensitive order using the java.util.Arrays.sort() method. Only a single argument required in this case for this method i.e. the array to be sorted. A program that demonstrates this is given as follows −
Example
import java.util.Arrays;
public class Demo {
public static void main(String args[]) {
String[] arr = new String[] { "apple", "mango", "Banana", "Melon", "orange" };
System.out.print("The unsorted array is: ");
System.out.println(Arrays.toString(arr));
Arrays.sort(arr);
System.out.print("The sorted array in case-sensitive order is: ");
System.out.println(Arrays.toString(arr));
}
}Output
The unsorted array is: [apple, mango, Banana, Melon, orange] The sorted array in case-sensitive order is: [Banana, Melon, apple, mango, orange]
Now let us understand the above program.
First the array arr[] is defined. Then the unsorted array is printed. A code snippet which demonstrates this is as follows −
String[] arr = new String[] { "apple", "mango", "Banana", "Melon", "orange" };
System.out.print("The unsorted array is: ");
System.out.println(Arrays.toString(arr));The Arrays.sort() method is used to sort the array in case-sensitive order. Then the sorted array is displayed. A code snippet which demonstrates this is as follows −
Arrays.sort(arr);
System.out.print("The sorted array in case-sensitive order is: ");
System.out.println(Arrays.toString(arr));
Updated on: 25-Jun-2020
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