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Java program to print all distinct elements of a given integer array in Java
All distinct elements of an array are printed i.e. all the elements in the array are printed only once and duplicate elements are not printed. An example of this is given as follows.
Array = 1 5 9 1 4 9 6 5 9 7 Distinct elements of above array = 1 5 9 4 6 7
A program that demonstrates this is given as follows.
Example
public class Example {
public static void main (String[] args) {
int arr[] = {1, 5, 9, 1, 4, 9, 6, 5, 9, 7};
int n = arr.length;
int i, j;
System.out.print("The array is: ");
for (i = 0; i < n; ++i)
System.out.print(arr[i] + " ");
System.out.print("
The distinct elements of above array are: ");
for (i = 0; i < n; i++) {
for (j = 0; j < i; j++)
if (arr[i] == arr[j])
break;
if (i == j)
System.out.print( arr[i] + " ");
}
}
}Output
The array is: 1 5 9 1 4 9 6 5 9 7 The distinct elements of above array are: 1 5 9 4 6 7
Now let us understand the above program.
First the original array is displayed. This array may contain duplicate elements. The code snippet that demonstrates this is given as follows −
System.out.print("The array is: ");
for (i = 0; i < n; ++i)
System.out.print(arr[i] + " ");Now, a nested for loop is used to make sure only distinct elements of the array are displayed. The outer loop runs from 0 to n and the inner loop makes sure that an element is printed only if has not occured before. The code snippet that demonstrates this is given as follows −
System.out.print("
The distinct elements of above array are: ");
for (i = 0; i < n; i++) {
for (j = 0; j < i; j++)
if (arr[i] == arr[j])
break;
if (i == j)
System.out.print( arr[i] + " ");
}
Updated on: 25-Jun-2020
4K+ Views
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