Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
Physics
Chemistry
Biology
Mathematics
English
Economics
Psychology
Social Studies
Fashion Studies
Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
Java Program to multiply integers and check for overflow
To check for Integer overflow, we need to check the Integer.MAX_VALUE with the multiplied integers result, Here, Integer.MAX_VALUE is the maximum value of an integer in Java.
Let us see an example wherein integers are multiplied and if the result is more than the Integer.MAX_VALUE, then an exception is thrown.
The following is an example showing how to check for Integer overflow.
Example
public class Demo {
public static void main(String[] args) {
int val1 = 9898;
int val2 = 6784;
System.out.println("Value1: "+val1);
System.out.println("Value2: "+val2);
long mul = (long)val1 * (long)val2;
if (mul > Integer.MAX_VALUE) {
throw new ArithmeticException("Overflow!");
}
// displaying multiplication
System.out.println("Multiplication Result: "+(int)mul);
}
}Output
Value1: 9898 Value2: 6784 Multiplication Result: 67148032
In the above example, we have taken the following two integers.
int val1 = 9898; int val2 = 6784;
Now we will cast and multiply them to a long.
long mul = (long)val1 + (long)val2;
If the result is more than the maximum value, then an exception is thrown.
If (mul > Integer.MAX_VALUE) {
throw new ArithmeticException("Overflow!");
}
Updated on: 26-Jun-2020
679 Views
Advertisements